Scraping web pages with python: Difference between revisions
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== Open a URL with lxml == | == Open a URL with lxml == | ||
<source lang="python"> | <source lang="python"> | ||
import html5lib, urllib2 | |||
def get (url): | def get (url): | ||
htmlparser = html5lib.HTMLParser(tree=html5lib.treebuilders.getTreeBuilder("lxml"), namespaceHTMLElements=False) | htmlparser = html5lib.HTMLParser(tree=html5lib.treebuilders.getTreeBuilder("lxml"), namespaceHTMLElements=False) |
Revision as of 16:28, 12 March 2012
Open a URL with lxml
import html5lib, urllib2
def get (url):
htmlparser = html5lib.HTMLParser(tree=html5lib.treebuilders.getTreeBuilder("lxml"), namespaceHTMLElements=False)
request = urllib2.Request(url)
request.add_header("User-Agent", "Mozilla/5.0 (X11; U; Linux x86_64; fr; rv:1.9.1.5) Gecko/20091109 Ubuntu/9.10 (karmic) Firefox/3.5.5")
f=urllib2.urlopen(request)
page = htmlparser.parse(f)
return page
Parsing with html5lib
The html5lib parser is code that turns the source text of an HTML page into a structured object, allowing, for instance, to use CSS selectors or xpath expressions to select/extract portions of a page
You can use xpath expressions:
import html5lib, lxml
htmlsource="<html><body><p>Example page.</p><p>More stuff.</p></body></html>"
htmlparser = html5lib.HTMLParser(tree=html5lib.treebuilders.getTreeBuilder("lxml"), namespaceHTMLElements=False)
page = htmlparser.parse(htmlsource)
p = page.xpath("/html/body/p[2]")
if p:
p = p[0]
print "".join([t for t in p.itertext()])
outputs: More stuff.
Also CSS selectors are possible:
import html5lib, lxml, lxml.cssselect
htmlsource="<html><body><p>Example page.</p><p>More stuff.</p></body></html>"
htmlparser = html5lib.HTMLParser(tree=html5lib.treebuilders.getTreeBuilder("lxml"), namespaceHTMLElements=False)
page = htmlparser.parse(htmlsource)
selector = lxml.cssselect.CSSSelector("p")
for p in selector(page):
print "-"*20
print "".join([t for t in p.itertext()])
-------------------- Example page. -------------------- More stuff.
Function that takes a URL + xpath
NB the function returns a LIST of matching fragments (since xpaths can potentially match multiple things). So, if you expect only one result, use [0] to pull off the first (single) item. lxml.etree.tostring is used to re-serialize the result.
import urllib2, html5lib, lxml, lxml.etree
def getXpath (url, xpath):
htmlparser = html5lib.HTMLParser(tree=html5lib.treebuilders.getTreeBuilder("lxml"), namespaceHTMLElements=False)
request = urllib2.Request(url)
request.add_header("User-Agent", "Mozilla/5.0 (X11; U; Linux x86_64; fr; rv:1.9.1.5) Gecko/20091109 Ubuntu/9.10 (karmic) Firefox/3.5.5")
f=urllib2.urlopen(request)
page = htmlparser.parse(f)
return page.xpath(xpath)
if __name__ == "__main__":
url = "http://www.jabberwocky.com/carroll/walrus.html"
xpath = "/html/body/p[6]"
print lxml.etree.tostring(getXpath(url, xpath)[0])
Function that takes a URL + CSS selector
import html5lib, lxml, lxml.cssselect
def getCSS (url, selector):
htmlparser = html5lib.HTMLParser(tree=html5lib.treebuilders.getTreeBuilder("lxml"), namespaceHTMLElements=False)
request = urllib2.Request(url)
request.add_header("User-Agent", "Mozilla/5.0 (X11; U; Linux x86_64; fr; rv:1.9.1.5) Gecko/20091109 Ubuntu/9.10 (karmic) Firefox/3.5.5")
f=urllib2.urlopen(request)
page = htmlparser.parse(f)
selector = lxml.cssselect.CSSSelector(selector)
return list(selector(page))
# TEST
if __name__ == "__main__":
url = "http://www.jabberwocky.com/carroll/walrus.html"
print lxml.etree.tostring(getCSS(url, "p")[0])