User:Δεριζαματζορπρομπλεμιναυστραλια/PrototypingnetworkedmediaSniff Scrape Crawl: Difference between revisions

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archive.org
From previous trimester i ve been looking the search of archive.org. Due to its size and variety of items
and collections the archive is difficult to be explored. Now i tried to understand more the structure
of the items and to see how can i look at them with python.
 
[[File:Allfilesia.png|framed|directory listing showing all original(by user), derived(by archive.org), and metadata files   
[[File:Allfilesia.png|framed|directory listing showing all original(by user), derived(by archive.org), and metadata files   
]]
]]
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'''Archive.org and python'''
'''Archive.org and python'''


found this code to open item in command line
found this code to open item in command line
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print webContent[0:500]
print webContent[0:500]
</source>
</source>


and then this for html output .
and then this for html output .
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'''internetarchive 0.6.6 =A python interface to archive.org
'''internetarchive 0.6.6 =A python interface to archive.org
'''
'''
1) ia for using the archive from the command line
1) ia for using the archive from the command line


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'''Accessing an IA Collection in Python
'''Accessing an IA Collection in Python
'''
'''
to see number of items:
to see number of items:
<source lang="python">  
<source lang="python">  
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item.download()
item.download()
</source>
</source>
'''Data mining'''
failed to install gevent error with vcvarsall.bat
ia mine can be used to  retrieve metadata for items via the IA Metadata API.
'''Get all links from a collection
'''
I also found this nice code!
(with beautiful soup)
<source lang="python">
import urllib2
from bs4 import BeautifulSoup
# Get the HTML for each list of results from the BPL collection. URLs look
# like this: http://archive.org/search.php?query=collection%3Abplscas&page=1
for resultsPage in range(1, 9768):
    url = "https://archive.org/search.php?query=collection%3Aopensource&page=" + str(resultsPage)
    response = urllib2.urlopen(url).read()
    soup = BeautifulSoup(response)
    links = soup.find_all(class_="titleLink")
    for link in links:
        itemURL = link['href']
        f = open('collections2nikos.txt','a')
        f.write('http://archive.org' + itemURL + '\n')
        f.close()
</source>
and with this we can get an html page with the links of each list of results.
next steps: to get the links from the results and attempt
to present them in another way?
SOURCES
https://pypi.python.org/pypi/internetarchive
http://blog.archive.org/2011/03/31/how-archive-org-items-are-structured/
http://programminghistorian.org/lessons/data-mining-the-internet-archive
http://programminghistorian.org/lessons/working-with-web-pages
http://wcm1.web.rice.edu/mining-bpl-antislavery.html

Latest revision as of 22:31, 29 June 2014

From previous trimester i ve been looking the search of archive.org. Due to its size and variety of items and collections the archive is difficult to be explored. Now i tried to understand more the structure of the items and to see how can i look at them with python.

directory listing showing all original(by user), derived(by archive.org), and metadata files

Items include multiple files dublin core or fuller marxml records that use the L.o.C. marc21 format for bibliographic data

Information about every file in this directory by viewing the file ending in _files.xml , all of the metadata for the item, view the file ending in _meta.xml :



Identifier

The globally unique ID of a given item on archive.org

collections and items all have a unique identifier

(taken by the Title field of the entry)

item: 251735-autopsy-0001-optimized collection: opensource_Afrikaans

Archive.org and python

found this code to open item in command line

 
 # open-webpage.py
import urllib2
url = 'https://archive.org/details/dasleidenunsersh00bras'
response = urllib2.urlopen(url)
webContent = response.read()
print webContent[0:500]

and then this for html output .

 
 # save-webpage.py
import urllib2
url = 'https://archive.org/details/bplill'
response = urllib2.urlopen(url)
webContent = response.read()
f = open('bplill.html', 'w')
f.write(webContent)
f.close


internetarchive 0.6.6 =A python interface to archive.org 1) ia for using the archive from the command line

2)internet archive for programmatic access to the archive

Accessing an IA Collection in Python to see number of items:

 
 import internetarchive
search = internetarchive.Search('collection:nasa')
print search.num_found

Accessing an item

 
ia download 251735-autopsy-0001-optimized (or types, mp4etc)
 
ia metadata  251735-autopsy-0001-optimized (metadata in command line)
 
import internetarchive
item = internetarchive.Item('251735-autopsy-0001-optimized')
item.download()

Data mining

failed to install gevent error with vcvarsall.bat

ia mine can be used to retrieve metadata for items via the IA Metadata API.


Get all links from a collection I also found this nice code! (with beautiful soup)

 
 import urllib2
from bs4 import BeautifulSoup
# Get the HTML for each list of results from the BPL collection. URLs look
# like this: http://archive.org/search.php?query=collection%3Abplscas&page=1
for resultsPage in range(1, 9768):
    url = "https://archive.org/search.php?query=collection%3Aopensource&page=" + str(resultsPage)
    response = urllib2.urlopen(url).read()
    soup = BeautifulSoup(response)
    links = soup.find_all(class_="titleLink")
    for link in links:
        itemURL = link['href']
        f = open('collections2nikos.txt','a')
        f.write('http://archive.org' + itemURL + '\n')
        f.close()

and with this we can get an html page with the links of each list of results.

next steps: to get the links from the results and attempt to present them in another way?



SOURCES https://pypi.python.org/pypi/internetarchive

http://blog.archive.org/2011/03/31/how-archive-org-items-are-structured/

http://programminghistorian.org/lessons/data-mining-the-internet-archive

http://programminghistorian.org/lessons/working-with-web-pages

http://wcm1.web.rice.edu/mining-bpl-antislavery.html